Surprisingly easy:
$ awk ‘function ceiling(x){return ((x > int(x)) ? int(x)+1 : int(x))}END{print ceiling(NR/2)}’ oneword_all.list
May 15, 2011
ceiling() in AWK.
Posted by mjhsieh at May 15, 2011 11:23 PM
Surprisingly easy:
$ awk ‘function ceiling(x){return ((x > int(x)) ? int(x)+1 : int(x))}END{print ceiling(NR/2)}’ oneword_all.list